Kinematics Question 608

Question: If the angles of projection of a projectile with same initial velocity exceed or fall short of $ 45{}^\circ $ by equal amounts , then the ratio of horizontal ranges it’s

Options:

A) $ 1:2 $

B)$ 1:3~ $

C) $ 1:4 $

D)$ 1:1 $

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Answer:

Correct Answer: D

Solution:

[d] For complementary angles of projection $ (45{}^\circ +\alpha ) $ and $ (45{}^\circ -\alpha ) $ with same initial velocity u, range R it’s same. $ {\theta _{1}}+{\theta _{2}}=( 45{}^\circ +\alpha)+( 45{}^\circ -\alpha)=90{}^\circ $



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