Kinematics Question 606

Question: A particle of mass M is projected with a velocity u making an angle of 30 with the horizontal. The magnitude of(Vh×h) of the projectile when the particle is at it’s maximum height h

Options:

A) 32v2g

B)zero

C) v22g

D) 316v2g

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Vh= V cosθ

Where h it’s the maximum height Vh×h=(vcosθ)(v2sin2θ2g)

=v3sin2θcosθ2g=3v316g



NCERT Chapter Video Solution

Dual Pane