Kinematics Question 593

Question: A particle has an initial velocity 3i^+4j^ and an acceleration of 0.4i^+0.3j^ . it’s speed after 10 sec is

Options:

A) 72 unit

B) 7 unit

C) 8.5 unit

D)10 unit

Show Answer

Answer:

Correct Answer: A

Solution:

[a] u=3i^+4j^ux=3 and uy=4

a=0.4i^+0.3j^ax=0.4

 and ay=0.3

So, Vx=ux+axt=3+0.4×10=3+4=7 .

Vy=uy+ayt=4+0.3×10=4+3=7

V=7i^+7j^

|V|=72+72=72 unit



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