SATHEE: Kinematics Question 586

Kinematics Question 586

Question: The resultant of vectors $\vec{P}$ and $\vec{Q}$ it’s $\vec{R}$ . On reversing the direction of $\vec{Q}$ , the resultant vector becomes $\vec{S}$ . Then, correct relation it’s

Options:

A) $R^{2} + S^{2} = (P^{2} + Q^{2})$

B) $R^{2} + S^{2} = P^{2} + Q^{2}$

C) $R^{2} + P^{2} = S^{2} + Q^{2}$

D) $P^{2} + S^{2} = 2 (Q^{2} + R^{2})$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] We have $R^{2} = P^{2} + Q^{2} + 2 P Q \cos θ \dots (i)$

$S^{2} = P^{2} + Q^{2} - P Q \cos θ \dots (i i)$

$Adding equations (i) and (ii) , we get$

$R^{2} + S^{2} = 2 (P^{2} + Q^{2}) .$

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Kinematics Question 586

Question: The resultant of vectors P→ and Q→ it’s R→ . On reversing the direction of Q→ , the resultant vector becomes S→ . Then, correct relation it’s

Options:

Answer:

Solution:

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Question: The resultant of vectors $\vec{P}$ and $\vec{Q}$ it’s $\vec{R}$ . On reversing the direction of $\vec{Q}$ , the resultant vector becomes $\vec{S}$ . Then, correct relation it’s