SATHEE: Kinematics Question 584

Kinematics Question 584

Question: The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to the vector $\vec{A}$ and it’s magnitude is equal to half the magnitude of vector $\vec{B}$ . The angle between $\vec{A}$ and $\vec{B}$ it’s

Options:

A) $120^{\circ}$

B) $150^{\circ}$

C) $135^{\circ}$

D) $180^{\circ}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $\frac{B}{2} = \sqrt{A^{2} + B^{2} +2AB cos θ}$ …… (i)

$∴ \tan 90^{\circ} = \frac{B \sin θ}{A+B cos θ} \Rightarrow A+B cos θ = 0$

$∴ \cos θ = - \frac{A}{B}$

Hence, from (i) $\frac{B^{2}}{A} = A^{2} + B^{2} - 2 A^{2}$ $\Rightarrow A= \sqrt{3} \frac{B}{2} \Rightarrow \cos θ = - \frac{A}{B} = - \frac{\sqrt{3}}{2}$ $∴ θ = 150^{\circ}$

Kinematics Question 584

Question: The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to the vector $\vec{A}$ and it’s magnitude is equal to half the magnitude of vector $\vec{B}$ . The angle between $\vec{A}$ and $\vec{B}$ it’s

Options:

Answer:

Solution:

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Kinematics Question 584

Question: The resultant of two vectors A→ and B→ is perpendicular to the vector A→ and it’s magnitude is equal to half the magnitude of vector B→ . The angle between A→ and B→ it’s

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to the vector $\vec{A}$ and it’s magnitude is equal to half the magnitude of vector $\vec{B}$ . The angle between $\vec{A}$ and $\vec{B}$ it’s