Kinematics Question 575

Question: A stone is projected horizontally with a $ \text{5 m/s} $ from the top of a plane inclined at an angle $ 45{}^\circ $ with the horizontal. How far from the point of projection will the particle strike the plane?

Options:

A)5$ \sqrt{2} $ m

B)11$ \sqrt{2} $ m

C) 12$ \sqrt{2} $ m

D)15$ \sqrt{2} $ m

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Answer:

Correct Answer: A

Solution:

[a] Range = $ \frac{2{\ u^{2}}}{g} $

${\text{g sin}\theta }=5\sqrt{2} $ m



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