Kinematics Question 569

Question: A body of mass 1 kg is moving in a vertical circular path of radius 1m. The difference between the kinetic energies at it’s highest and lowest position it’s

Options:

A) 20J

B)10J

C) 45J

D) 10(51)J

Show Answer

Answer:

Correct Answer: A

Solution:

Difference in kinetic energy = 2mgr=2×1×10×1=20J



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