SATHEE: Kinematics Question 566

Kinematics Question 566

Question: The maximum and minimum tension in the string whirling in a circle of radius 2.5 m with constant velocity are in the ratio 5 : 3 then it’s velocity is [Pb. PET 2003]

Options:

A) $\sqrt{98} m / s$

B) $7 m / s$

C) $\sqrt{490} m / s$

D) $\sqrt{4.9}$

Show Answer

Answer:

Correct Answer: A

Solution:

In this problem it’s assumed that particle although moving in a vertical loop but it’s speed remain constant. Tension at lowest point $T_{max} = \frac{m v^{2}}{r} + m g$ Tension at highest point $T_{min} = \frac{m v^{2}}{r} - m g$

$\frac{T_{max}}{T_{min}} = \frac{\frac{m v^{2}}{r} + m g}{\frac{m v^{2}}{r} - m g} = \frac{5}{3}$ by solving we get, $v = \sqrt{4 g r}$

$= \sqrt{4 \times 9.8 \times 2.5}$

$= \sqrt{98} m / s$

Kinematics Question 566

Question: The maximum and minimum tension in the string whirling in a circle of radius 2.5 m with constant velocity are in the ratio 5 : 3 then it’s velocity is [Pb. PET 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Kinematics Question 566

Question: The maximum and minimum tension in the string whirling in a circle of radius 2.5 m with constant velocity are in the ratio 5 : 3 then it’s velocity is [Pb. PET 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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