Kinematics Question 560

Question: A particle is moving in a vertical circle.The tensions in the string when passing through two positions at angles$ 30^{o} $ and $ 60^{o} $ from vertical (lowest position) are $ T _{1} $ and $ T _{2} $ respectively.then[Or it’ssa JEE 2002]

Options:

A)$ T _{1}=T _{2} $

B) $ T _{2}>T _{1} $

C) $ T _{1}>T _{2} $

D) Tension in the string always remains the same

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Answer:

Correct Answer: C

Solution:

Tension, $ T=\frac{mv^{2}}{r}+mg\cos \theta $

For, $ \theta =30{}^\circ ,T _{1}=\frac{mv^{2}}{r}+mg\cos 30{}^\circ $

$ \theta =60{}^\circ ,T _{2}=\frac{mv^{2}}{r}+mg\cos 60{}^\circ \therefore T _{1}>T _{2} $



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