Kinematics Question 546

Question: If the equation for the displacement of a particle moving on a circular path it’s given by (θ)=2t3+0.5 , where θ it’s in radians and t in seconds, then the angular velocity of the particle after 2 sec froM is start it’s[AIIMS 1998]

Options:

A) 8 rad/sec

B)12 rad/sec

C) 24 rad/sec

D)36 rad/sec

Show Answer

Answer:

Correct Answer: C

Solution:

ω=dθdt=ddt(2t3+0.5)=6t2 at t =2 s, ω=6×(2)2=24rad/s



NCERT Chapter Video Solution

Dual Pane