Kinematics Question 542

Question: The string of pendulum of length $ l $ it’s d it’splaced through $ 90^{o} $ from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position it’s[MP PMT 1986]

Options:

A) $ mg $

B)$ 3mg $

C) $ 5mg $

D) $ 6mg $

Show Answer

Answer:

Correct Answer: B

Solution:

$ T=mg+\frac{mv^{2}}{l} $

$ =mg+2mg=3mg $ where $ v=\sqrt{2gl} $ from $ \frac{1}{2}mv^{2}=mgl $



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