Kinematics Question 537

Question: A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N, when the stone is at (g = 10 m/sec2) [AIIMS 1982]

Options:

A) Top of the circle

B) Bottom of the circle

C) Half way down

D)None of the above

Show Answer

Answer:

Correct Answer: A

Solution:

mg=1×10=10N,

mv2r=1×(4)21=16

Tension at the top of circle = mv2rmg=6N

Tension at the bottom of circle = mv2r+mg=26N



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