Kinematics Question 519

Question: A boy projects a stone vertically perpendicular to the trolley car with a speed $ v $ . If the trolley car moves with $ u $ constant velocity m, the time of flight of the stone is:

Options:

A) $ \frac{u+v}{g} $

B) $ \frac{2v}{g} $

C) $ \frac{2u}{g} $

D) none of these

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ v _{0}\sin \theta =v $

$ v _{0}\cos \theta =u $

Time of flight depends on vertical component of velocity. $ T=\frac{2v _{0}\sin \theta }{g}=\frac{2v}{g} $



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