Kinematics Question 512

Question: A man standing on the roof of a house of height $ h $ throws one particle vertically downwards and another particle horizontally with the same velocity u. The ratio of their velocities when they reach the earth’s surface will be

Options:

A) $ \sqrt{2gh+{u _{^{^{{}}}}}^{2}}:u $

B) $ 1:2 $

C) $ 1:1 $

D) $ \sqrt{2gh+u^{2}}:\sqrt{2gh} $

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Answer:

Correct Answer: C

Solution:

[c] When particle is thrown in vertical downward direction with velocity u, then the final velocity at the ground level it’s $ v^{2}=u^{2}+2gh $

$ \therefore v=\sqrt{u^{2}+2gh} $

Another particle is thrown horizontally with same velocity then at the surface of earth.

Horizontal component of velocity $ v _{x}=u $

Therefore, resultant velocity, $ v=\sqrt{u^{2}+2gh} $

For both the particles, final velocities when they reach the earth’ surface are equal.



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