Kinematics Question 445

Question: Given that X $ \vec{A}+\vec{B}+\vec{C} $ = 0, out of three vectors two are equal in magnitude and the magnitude of third vector is $ \sqrt{2} $ times that of either of two having equal magnitude. Then, angle between vectors are given by

Options:

A) $ 30{}^\circ ,60{}^\circ ,90{}^\circ $

B) $ 45{}^\circ ,45{}^\circ ,90{}^\circ $

C) $ 90{}^\circ ,135{}^\circ ,45{}^\circ $

D) $ 90{}^\circ ,135{}^\circ ,135{}^\circ $

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Answer:

Correct Answer: D

Solution:

[d] Angle between $ \vec{A} $ and $ \vec{B} $ it’s $ 90^{o} $

Between $ \vec{B} $ and $ \vec{C} $ it’s $ 135{}^\circ $

and that between $ \vec{A} $ and $ \vec{C} $ it’s $ 135{}^\circ $ .



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