Kinematics Question 425
Question: A particle moves along a path ABCD . Then the magnitude of net displacement of the particle from position A to D it’s:
Options:
A) 10 m
B) $ 5\sqrt{2}m $
C) 9 m
D) $ 7\sqrt{2}m $
Correct Answer: D [d] The displacement is $ \sqrt{{{(AF)}^{2}}+{{(FD)}^{2}}}=7\sqrt{2}m $ .
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