SATHEE: Kinematics Question 425

Kinematics Question 425

Question: A particle moves along a path ABCD . Then the magnitude of net displacement of the particle from position A to D it’s:

Options:

A) 10 m

B) $5 \sqrt{2} m$

C) 9 m

D) $7 \sqrt{2} m$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] The displacement is $\sqrt{{(A F)}^{2} + {(F D)}^{2}} = 7 \sqrt{2} m$ .

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Kinematics Question 425

Question: A particle moves along a path ABCD . Then the magnitude of net displacement of the particle from position A to D it’s:

Options:

Answer:

Solution:

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