Kinematics Question 416

Question: A body a is thrown vertically upward with the initial velocity v1 . Another body b is dropped from a height h. Find how the distance x between the bodies depends on the time t if the bodies begin to move simultaneously.

Options:

A) x=hv1t

B) x=(hv1)t

C) x=hv1t

D) x=htv1

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Answer:

Correct Answer: A

Solution:

The distance travelled by the body a is A,

given by v1t=gt22 and that travelled by the body b is h2=gt22 s

The distance between the bodies =x=h(h1+h2). Since h1+h2=v1t ,

the relation sought it’s x=hv1t



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