SATHEE: Kinematics Question 401

Kinematics Question 401

Question: A man throws balls with same speed vertically upwards one after the other at an interval of 2 sec. What should be the speed of throw so that more man two balls are in air at any time?

Options:

A) Only with speed 19.6 m/s

B) More than 19.6 m/s

C) At least 9.8 m/s

D) Any speed less than 19.6 m/s.

Show Answer

Answer:

Correct Answer: B

Solution:

Height attained by balls in 2 sec is $= \frac{1}{2} \times 9.8 \times 4 = 19.6 m$ The same distance will be covered in 2 second (for descent) Time interval of throwing balls, remaining same. So, for two balls remaining in air, the time of ascent or descent must be greater than 2 seconds. Hence speed of balls must be greater than $19.6 m / s e c$ .

Kinematics Question 401

Question: A man throws balls with same speed vertically upwards one after the other at an interval of 2 sec. What should be the speed of throw so that more man two balls are in air at any time?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Kinematics Question 401

Question: A man throws balls with same speed vertically upwards one after the other at an interval of 2 sec. What should be the speed of throw so that more man two balls are in air at any time?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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