Kinematics Question 379

Question: Starting from rest a particle moves in a straight line with acceleration a=(25t2)1/2m/s2 for 0t5s , a=3π8m/s2 for t>5s . The velocity of particle at t=7s it’s:

Options:

A) 11 m/s

B) 22 m/s

C) 33 m/s

D) 44 m/s

Show Answer

Answer:

Correct Answer: B

Solution:

V7=V5+3π8×2 To calculate V5 i.e. velocity at end of 5 sec.

a=(25t2)1/2

dvdt=(25t2)1/2



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