Kinematics Question 375

Question: The acceleration of a particle, starting from rest, varies with time according to the relation a=sω2sinωt . The displacement of this particle at a time t will be

Options:

A) s sin ω t

B) ω cos ω t

C) ω sinωt

D) 12(sω2 sin ωt)t2

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Answer:

Correct Answer: A

Solution:

a=d2xdt2=sωsinωt.

On integrating, dxdt=sω2cosωtω=ssinωt

Again on integrating, we get x=sωsinωtω=ssinωt



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