Kinematics Question 372

Question: A particle starting with certain initial velocity and uniform acceleration covers a distance of 12 m in first 3 seconds and a distance of 30 m in next 3 seconds. The initial velocity of the particle is

Options:

A) 3ms1

B) 2.5ms1

C) 2ms1

D) ms1

Show Answer

Answer:

Correct Answer: D

Solution:

Let u be the initial velocity that have to find and a be the uniform acceleration of the particle. For t=3s , distance travelled

S=12m and For t=3+3=6s

distance travelled S=12+30=42m From, S=ut+1/2at2

12=u×3+12×a×32

Or 24=6y+9a               (i)

Similarly, 42=u×6+12×a×62

Or 42=6y+18a                  (ii) On solving, we get u=1ms1



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