Kinematics Question 370

Question: A metro train starts from rest and in 5 s achieves 108 km/h. After that it moves with constant velocity and comes to rest after travelling 45 m with uniform retardation. If total distance travelled is 395 m, find total time of travelling.

Options:

A) 12.2s

B) 15.3s

C) 9s

D) 17.2s

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Answer:

Correct Answer: D

Solution:

Given: u=0,

t=5sec,

v=108km/hr

=30m/s By equation of motion v=u+at

or a=vt=3056 m/s2[u=0]

S1=12at2=12×6×52=75 m

distance travelled in first 5 sec is 75m. distance travelled with uniform speed of 30 m/s it’s S2

395=S1+S2+S3395=75+S2+45
S2=275 m

Time taken to travel 275 m =27530 = 9.2 sec For retarding motion, we have 02302=2(a)×45, we get a = 10 m/s2

S=ut+12at245=30t+12(10)t2
45=30t5t2

On solving we get, t=3sec Total time taken =5+9.2+3=17.2sec.



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