SATHEE: Kinematics Question 362

Kinematics Question 362

Question: A car accelerates from rest at a constant rate $α$ for some time, after which it decelerates at a constant rate $β$ and comes to rest. If the total time elapsed it’s t, then the maximum velocity acquired by the car it’s

Options:

A) $(\frac{α^{2} + β^{2}}{α β}) t$

B) $(\frac{α^{2} - β^{2}}{α β})$

C) $\frac{(α^{} + β^{}) t}{α β}$

D) $\frac{α β t}{α^{} + β^{}}$

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Answer:

Correct Answer: D

Solution:

In fig., $A . A_{1} = v_{m a x .}$

= $α t_{1}$ = $β t_{2}$

$But t= t_{1} + t_{2} = \frac{V_{max}}{α} + \frac{V_{max}}{β}$

$= v_{max} (\frac{1}{α} + \frac{1}{β}) = v_{max} (\frac{α + β}{α β})$

$o r, v_{max} = t (\frac{α β}{α + β})$

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Kinematics Question 362

Question: A car accelerates from rest at a constant rate α for some time, after which it decelerates at a constant rate β and comes to rest. If the total time elapsed it’s t, then the maximum velocity acquired by the car it’s

Options:

Answer:

Solution:

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Question: A car accelerates from rest at a constant rate $α$ for some time, after which it decelerates at a constant rate $β$ and comes to rest. If the total time elapsed it’s t, then the maximum velocity acquired by the car it’s