Kinematics Question 357
Question: If a train travelling at $ 20m/s $ it’s to be brought to rest in a distance of 200 m, then it’s retardation should be
Options:
A) $ 1m/s^{2} $
B) $ 2m/s^{2} $
C) $ 10m/s^{2} $
D) $ 20m/s^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ v^{2}-{{u}^{2}}\text{= 2aS} $
$ \Rightarrow a=\frac{{{u}^{2}}}{2aS}=\frac{{{( 20 )}^{2}}}{2\times 200}=1m/s^{2} $
