Kinematics Question 338

Question: A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $ s _{1} $ in the first 10 seconds and distance $ s _{2} $ in the next 10 seconds, then

Options:

A) $ s _{2}=s _{1} $

B) $ s _{2}=2s _{1} $

C) $ s _{2}=3s _{1} $

D) $ s _{2}=4s _{1} $

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Answer:

Correct Answer: C

Solution:

Let a be the constant acceleration of the particle. Then

$ \text{s=ut+}\frac{1}{2}a{{t}^{2}} $ or

$ {{s} _{1}}\text{=0+}\frac{1}{2}\times\text{ a }\times{{( 10 )}^{2}}\text{=50 a} $

and $ {{s} _{2}}=[ \text{0+}\frac{1}{2}a{{( 20 )}^{2}} ]-\text{50a=150a} $

$ \therefore s _{2}=3s _{1} $



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