Kinematics Question 33
Question: Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces? Also name the triangle formed by the forces as sides [JIPMER 2000]
Options:
A) $ 60{}^\circ $ equilateral triangle
B) $ 120{}^\circ $ equilateral triangle
C) $ 120{}^\circ $ , $ 30{}^\circ $ , $ 30{}^\circ $ an isosceles triangle
D) $ 120{}^\circ $ an obtuse angled triangle
Correct Answer: A In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given $ \theta =\frac{360}{N} $ $ =\frac{360}{3}=120{}^\circ $ If these three vectors are represented by three sides of triangle then they form equilateral triangle
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