Kinematics Question 305

Question: A force F→=(5i^+3j^) N it’s applied over a particle which d it’splaces it froM is original position to the point s→=(2i^−1j^) m. The work done on the particle is [BHU 2001]

Options:

A) 12

B) 6

C) 1

D) 0

Show Answer

Answer:

Correct Answer: A

Solution:

W=F→.s→=(3i^+cj^+2k^).(−4i^+2j^−3k^)

=−12+2c−6

Work done =6J (given)
∴ −12+2c−6=6
⇒ c=12

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