A) 90°
B) 0°
C) 180°
D) 60°
Correct Answer: D $ \cos \theta =\frac{\vec{A}.\vec{B}}{|\vec{A}||\vec{B}|}=\frac{1}{\sqrt{2}\sqrt{2}}=\frac{1}{2} $ $ \theta =60{}^\circ $
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