Kinematics Question 281
Question: The resultant of the two vectors having magnitude 2 and 3 it’s 1. What is their cross product
Options:
A) 6
B) 3
C) 1
D) 0
Correct Answer: D $ \sqrt{2^{2}+3^{2}+2\times 2\times 3\times \cos \theta }=1 $ By solving we get $ \theta =180{}^\circ $ \ $ \vec{A}\times \vec{B}=0 $
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