SATHEE: Kinematics Question 28

Kinematics Question 28

Question: A scooter going due east at 10 ms?1 turns right through an angle of 90°. If the speed of the scooter remains unchanged in taking turn, the change it’s the velocity of the scooter it’s [BHU 1994]

Options:

A) $20.0 m s^{1}$ south eastern direction

B) Zero

C) $10.0 m s^{1}$ in southern direction

D) $14.14 m s^{1}$ in south-west direction

Show Answer

Answer:

Correct Answer: D

Solution:

If the magnitude of vector remains same, only direction change by $θ$ then $\vec{Δ v} = \vec{v_{2}} - \vec{v_{1}}$ , $\vec{Δ v} = \vec{v_{2}} + (- \vec{v_{1})}$

Magnitude of change in vector $| \vec{Δ v} | = 2 v \sin (\frac{θ}{2})$

$| \vec{Δ v} | = 2 \times 10 \times \sin (\frac{90^{\circ}}{2})$ = $10 \sqrt{2}$ = $14.14 m / s$

direction is south-west .

Kinematics Question 28

Question: A scooter going due east at 10 ms?1 turns right through an angle of 90°. If the speed of the scooter remains unchanged in taking turn, the change it’s the velocity of the scooter it’s [BHU 1994]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Kinematics Question 28

Question: A scooter going due east at 10 ms?1 turns right through an angle of 90°. If the speed of the scooter remains unchanged in taking turn, the change it’s the velocity of the scooter it’s [BHU 1994]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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