Kinematics Question 271
Question: If $ \overrightarrow{P}.\overrightarrow{Q}=PQ, $ then angle between $ \overrightarrow{P} $ and $ \overrightarrow{Q} $ it’s [AIIMS 1999]
Options:
A) 0°
B) 30°
C) 45°
D) 60°
Correct Answer: A $ \cos \theta =\frac{\vec{P}.\vec{Q}}{PQ}=1 $ $ \theta =0{}^\circ $
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