SATHEE: Kinematics Question 237

Kinematics Question 237

Question: A man drops a ball downside from the roof of a tower of height 400 meters. At the same time another ball is thrown upside with a velocity 50 meter/sec. from the surface of the tower, then they will meet at which height from the surface of the tower [CPMT 2003]

Options:

A) 100 meters

B) 320 meters

C) 80 meters

D) 240 meters

Show Answer

Answer:

Correct Answer: C

Solution:

Let both balls meet at point P after time t. The distance travelled by ball A, $h_{1} = \frac{1}{2} g t^{2}$ The distance travelled by ball B, $h_{2} = u t - \frac{1}{2} g t^{2}$

$h_{1} + h_{2} = 400 m$

therefore $u t = 400, t = 400 / 50 = 8 s e c$
$∴$ $h_{1} = 320 m A n d h_{2} = 80 m$

Kinematics Question 237

Question: A man drops a ball downside from the roof of a tower of height 400 meters. At the same time another ball is thrown upside with a velocity 50 meter/sec. from the surface of the tower, then they will meet at which height from the surface of the tower [CPMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Kinematics Question 237

Question: A man drops a ball downside from the roof of a tower of height 400 meters. At the same time another ball is thrown upside with a velocity 50 meter/sec. from the surface of the tower, then they will meet at which height from the surface of the tower [CPMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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