Kinematics Question 232

Question: A ball is dropped from top of a tower of 100m height. Simultaneously another ball was thrown upward from bottom of the tower with a speed of 50 m/s ( $ g=10m/s^{2}) $ . They will cross each other after [Or it’ssa JEE 2002]

Options:

A) $ 1s $

B) $ 2s $

C) $ 3s $

D) $ 4s $

Show Answer

Answer:

Correct Answer: B

Solution:

$ h _{1}=\frac{1}{2}gt^{2} $ , $ h _{2}=50t-\frac{1}{2}gt^{2} $

Given $ h _{1}+h _{2}=100m $

therefore $ 50t=100\Rightarrow t=2\ \sec $



NCERT Chapter Video Solution

Dual Pane