SATHEE: Kinematics Question 203

Kinematics Question 203

Question: A rocket it’s fired upward from the earth’s surface such that it creates an acceleration of 19.6 m/sec2. If after 5 sec is engine it’s switched off, the maximum height of the rocket from earth’s surface would be [MP PET 1995]

Options:

A) 245 m

B) 490 m

C) 980 m

D) 735 m

Show Answer

Answer:

Correct Answer: D

Solution:

Given $a = 19.6 m / s^{2} = 2 g$

Resultant velocity of the rocket after 5 sec $v = 2 g \times 5 = 10 g m / s$

Height achieved after 5 sec, $h_{1} = \frac{1}{2} \times 2 g \times 25 = 245 m$

On switching off the engine it goes up to height $h_{2}$ where it’s velocity becomes zero.

$0 = {(10 g)}^{2} - 2 g h_{2} \Rightarrow h_{2} = 490 m$
$∴$ Total height of rocket $= 245 + 490 = 735 m$

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Kinematics Question 203

Question: A rocket it’s fired upward from the earth’s surface such that it creates an acceleration of 19.6 m/sec2. If after 5 sec is engine it’s switched off, the maximum height of the rocket from earth’s surface would be [MP PET 1995]

Options:

Answer:

Solution:

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