Kinematics Question 203

Question: A rocket it’s fired upward from the earth’s surface such that it creates an acceleration of 19.6 m/sec2. If after 5 sec is engine it’s switched off, the maximum height of the rocket from earth’s surface would be [MP PET 1995]

Options:

A) 245 m

B) 490 m

C) 980 m

D) 735 m

Show Answer

Answer:

Correct Answer: D

Solution:

Given $ a=19.6\ m/s^{2}=2g $

Resultant velocity of the rocket after 5 sec $ v=2g\times 5=10g\ m/s $

Height achieved after 5 sec, $ h _{1}=\frac{1}{2}\times 2g\times 25=245m $

On switching off the engine it goes up to height $ h _{2} $ where it’s velocity becomes zero.

$ 0={{(10g)}^{2}}-2gh _{2}\Rightarrow h _{2}=490m $
$ \therefore $ Total height of rocket $ =245+490=735\ m $



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