SATHEE: Kinematics Question 167

Kinematics Question 167

Question: Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration $2 m / s^{2}$ . If B starts at $t = 10$ and A starts from the same point at $t = 10$ s, then the time during the journey in which A was ahead of b is

Options:

A) 20 s

B) 8 s

C) 10 s

D) a is never ahead of B

Show Answer

Answer:

Correct Answer: D

Solution:

[d] A will be ahead or B when $x_{A} \geq x_{B}$

$40 (t - 10) \geq (0) t + \frac{1}{2} (2) t^{2}$ As a is 10 sec late than B.
$\Rightarrow t^{2} - 40 t + 400 \leq 0$
$\Rightarrow {(t - 20)}^{2} \leq 0$ Which is not possible, so A will never be ahead at B.

Kinematics Question 167

Question: Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration $2 m / s^{2}$ . If B starts at $t = 10$ and A starts from the same point at $t = 10$ s, then the time during the journey in which A was ahead of b is

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Sample Mock Test

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NCERT Exercise Video Solution

Kinematics Question 167

Question: Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration 2m/s2 . If B starts at t=10 and A starts from the same point at t=10 s, then the time during the journey in which A was ahead of b is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Two bikes A and B start from a point. A moves with uniform speed 40 m/s and B starts from rest with uniform acceleration $2 m / s^{2}$ . If B starts at $t = 10$ and A starts from the same point at $t = 10$ s, then the time during the journey in which A was ahead of b is