Kinematics Question 156

Question: The tension in the horizontal cord it’s 30 N. The weight W and tension in the string OA in Newton are [DPMT 1992]

Options:

A) 30 $ \sqrt{3}, $ 30

B) 30 $ \sqrt{3}, $ 60

C) 60 $ \sqrt{3}, $ 30

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$ T\sin 30^{o}=30 $ -(i)

$ T\cos 30^{o}=W $ -(ii)

By solving equation (i) and (ii) we get $ W=30\sqrt{3}N $ and $ T=60N $



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