Kinematics Question 154

Question: P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given P = 1.9318 kg wt, $ \sin {\theta_1}= $ 0.9659, the value of R it’s ( in kg wt) [CET 1998]

Options:

A) 0.9659

B) 2

C) 1

D) $ \frac{1}{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{P}{\sin {\theta_1}}=\frac{Q}{\sin {\theta_2}}=\frac{R}{\sin 150{}^\circ } $

$ \Rightarrow \frac{1.93}{\sin {\theta_1}}=\frac{R}{\sin 150{}^\circ } $

$ \Rightarrow R=\frac{1.93\times \sin 150{}^\circ }{\sin {\theta_1}}=\frac{1.93\times 0.5}{0.9659}=1 $



NCERT Chapter Video Solution

Dual Pane