Kinematics Question 149
Question: The angle between the two vectors $ \vec{A}=3\hat{i}+4\hat{j}+5\hat{k} $ and $ \vec{B}=3\hat{i}+4\hat{j}+5\hat{k} $ it’s [DPMT 2000]
Options:
A) 60°
B) Zero
C) 90°
D) None of these
Correct Answer: D $ \cos \theta =\frac{\overrightarrow{A}.\overrightarrow{B}}{|A||B|}=\frac{9+16+25}{\sqrt{9+16+25}\sqrt{9+16+25}} $ = $ \frac{50}{50}=1 $
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Answer:
Solution:
therefore $ \cos \theta =1 $
$ \therefore $ $ \theta ={{\cos }^{-1}}(1) $
