Kinematics Question 142

Question: The position vector of a particle is r=(acosωt)i^+(asinωt)j^ . The velocity of the particle is [CBSE PMT 1995]

Options:

A) Parallel to the position vector

B) Perpendicular to the position vector

C) Directed towards the origin

D) Directed away from the origin

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Answer:

Correct Answer: B

Solution:

r=(acosωt)i^+(asinωt)j^

v=drdt=aωsinωti^+aωcosωtj^

As r.v=0

therefore velocity of the particle is perpendicular to the position vector.



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