Kinematics Question 135

Question: The expression $ ( \frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j} ) $ it’s a

Options:

A) Unit vector

B) Null vector

C) Vector of magnitude $ \sqrt{2} $

D) Scalar

Show Answer

Answer:

Correct Answer: A

Solution:

$ \vec{P}=\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j} $

$ |\vec{P}|=\sqrt{{{( \frac{1}{\sqrt{2}} )}^{2}}+{{( \frac{1}{\sqrt{2}} )}^{2}}} $ = 1

its a unit vector.



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