SATHEE: Kinematics Question 127

Kinematics Question 127

Question: If $A = 3 \hat{i} + 4 \hat{j}$ and $B = 7 \hat{i} + 24 \hat{j},$ the vector having the same magnitude as B and parallel to a is

Options:

A) $5 \hat{i} + 20 \hat{j}$

B) $15 \hat{i} + 10 \hat{j}$

C) $20 \hat{i} + 15 \hat{j}$

D) $15 \hat{i} + 20 \hat{j}$

Show Answer

Answer:

Correct Answer: D

Solution:

$| B | = \sqrt{7^{2} + {(24)}^{2}}$

$= \sqrt{625}$

$= 25$ Unit vector in the direction of A will be $\hat{A} = \frac{3 \hat{i} + 4 \hat{j}}{5}$

So required vector = $25 (\frac{3 \hat{i} + 4 \hat{j}}{5})$

$= 15 \hat{i} + 20 \hat{j}$

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Kinematics Question 127

Question: If A=3i^+4j^ and B=7i^+24j^, the vector having the same magnitude as B and parallel to a is

Options:

Answer:

Solution:

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Question: If $A = 3 \hat{i} + 4 \hat{j}$ and $B = 7 \hat{i} + 24 \hat{j},$ the vector having the same magnitude as B and parallel to a is