SATHEE: Kinematics Question 119

Kinematics Question 119

Question: A person moves 30 m north and then 20 m towards east and finally $30 \sqrt{2}$ m in south-west direction. The displacement of the person from the origin will be [J & K CET 2004]

Options:

A) 10 m along north

B) 10 m long south

C) 10 m along west

D) Zero

Show Answer

Answer:

Correct Answer: C

Solution:

$\vec{O A} = 0 \vec{i} + 30 \vec{j}$ , $\vec{A B} = 20 \vec{i} + 0 \vec{j}$

$\vec{B C} = - 30 \sqrt{2} c o s 45^{o} \vec{i}$

$- 30 \sqrt{2} \sin 4 5^{o} \vec{j}$

$= - 30 \vec{i} - 30 \vec{j}$ \ Net displacement, $\vec{O C} = \vec{O A} + \vec{A B} + \vec{B C}$

$= - 10 \vec{i} + 0 \vec{j}$

$| \vec{O C} | = 10 m .$

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Kinematics Question 119

Question: A person moves 30 m north and then 20 m towards east and finally 302 m in south-west direction. The displacement of the person from the origin will be [J & K CET 2004]

Options:

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Question: A person moves 30 m north and then 20 m towards east and finally $30 \sqrt{2}$ m in south-west direction. The displacement of the person from the origin will be [J & K CET 2004]