SATHEE: Kinematics Question 118

Kinematics Question 118

Question: A man goes 10m towards North, then 20m towards east then displacement is [KCET 1999; JIPMER 1999; AFMC 2003]

Options:

A) 22.5m

B) 25m

C) 25.5m

D) 30m

Show Answer

Answer:

Correct Answer: A

Solution:

$\vec{r} = 20 \hat{i} + 10 \hat{j}$
$∴$

$r = \sqrt{20^{2} + 10^{2}} = 22.5$ m

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Kinematics Question 118

Question: A man goes 10m towards North, then 20m towards east then displacement is [KCET 1999; JIPMER 1999; AFMC 2003]

Options:

Answer:

Solution:

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