SATHEE: Kinematics Question 113

Kinematics Question 113

Question: A particle moves towards east with velocity 5 m/s. After 10 seconds is direction changes towards north with same velocity. The average acceleration of the particle is [CPMT 1997; IIT-JEE 1982]

Options:

A) Zero

B) $\frac{1}{\sqrt{2}} m / s^{2} N - W$

C) $\frac{1}{\sqrt{2}} m / s^{2} N - E$

D) $\frac{1}{\sqrt{2}} m / s^{2} S - W$

Show Answer

Answer:

Correct Answer: B

Solution:

$Δ v = 2 v \sin (\frac{θ}{2}) = 2 \times 5 \times \sin 45^{\circ}$ = $\frac{10}{\sqrt{2}}$ \ $a = \frac{Δ v}{Δ t} = \frac{10 / \sqrt{2}}{10} = \frac{1}{\sqrt{2}} m / s^{2}$

Kinematics Question 113

Question: A particle moves towards east with velocity 5 m/s. After 10 seconds is direction changes towards north with same velocity. The average acceleration of the particle is [CPMT 1997; IIT-JEE 1982]

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Other Resources

Syllabus

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Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Kinematics Question 113

Question: A particle moves towards east with velocity 5 m/s. After 10 seconds is direction changes towards north with same velocity. The average acceleration of the particle is [CPMT 1997; IIT-JEE 1982]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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