Kinematics Question 107

Question: If a vector $ \overrightarrow{P} $ making angles a, b, and g respectively with the X, Y and Z axes respectively. Then $ {{\sin }^{2}}\alpha +{{\sin }^{2}}\beta +{{\sin }^{2}}\gamma = $

Options:

A) 0

B) 1

C) 2

D) 3

Show Answer

Answer:

Correct Answer: C

Solution:

$ {{\sin }^{2}}\alpha +{{\sin }^{2}}\beta +\sin \gamma $

$ =1-{{\cos }^{2}}\alpha +1-{{\cos }^{2}}\beta +1-{{\cos }^{2}}\gamma $

$ =3-({{\cos }^{2}}\alpha +{{\cos }^{2}}\beta +{{\cos }^{2}}\gamma ) $

$ =3-1=2 $



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