SATHEE: Gravitation Question 58

Gravitation Question 58

Question: Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.If the ratio of densities of earth $[(ρ_{e})]$ and moon $[(ρ_{m})]$ is $[(\frac{ρ_{e}}{ρ_{m}}) = \frac{5}{3}]$ then radius of moon Rm in terms of Re will be [MP PMT 2003]

Options:

A) $[\frac{5}{18} R_{e}]$

B) $[\frac{1}{6} R_{e}]$

C) $[\frac{3}{18} R_{e}]$

D) $[\frac{1}{2 \sqrt{3}} R_{e}]$

Show Answer

Answer:

Correct Answer: A

Solution:

$[g = \frac{4}{3} π G ρ R]$ $[\Rightarrow,, g \propto ρ R, \Rightarrow, \frac{g_{e}}{g_{m}} = \frac{ρ_{e}}{ρ_{m}} \times \frac{R_{e}}{R_{m}}]$ $[\Rightarrow,, \frac{6}{1} = \frac{5}{3} \times \frac{R_{e}}{R_{m}}, \Rightarrow,, R_{m} = \frac{5}{18} R_{e}]$

Gravitation Question 58

Question: Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.If the ratio of densities of earth $[(ρ_{e})]$ and moon $[(ρ_{m})]$ is $[(\frac{ρ_{e}}{ρ_{m}}) = \frac{5}{3}]$ then radius of moon Rm in terms of Re will be [MP PMT 2003]

Options:

Answer:

Solution:

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Gravitation Question 58

Question: Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.If the ratio of densities of earth [(ρe)] and moon [(ρm)] is [(ρeρm)=53] then radius of moon Rm in terms of Re will be [MP PMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.If the ratio of densities of earth $[(ρ_{e})]$ and moon $[(ρ_{m})]$ is $[(\frac{ρ_{e}}{ρ_{m}}) = \frac{5}{3}]$ then radius of moon Rm in terms of Re will be [MP PMT 2003]