SATHEE: Gravitation Question 49

Gravitation Question 49

Question: The angular speed of earth, so that the object on equator may appear weightless, is $[(g = 10, m / s^{2}]$ , radius of earth 6400 km)[Pb. PMT 2001]

Options:

A) $[1.25 \times 10^{- 3} r a d / s e c]$

B) $[1.56 \times 10^{- 3} r a d / s e c]$

C) $[1.25 \times 10^{- 1} r a d / s e c]$

D) 1.56 rad/sec

Show Answer

Answer:

Correct Answer: A

Solution:

For condition of weightlessness of equator

$[ω = \sqrt{\frac{g}{R}} = \frac{1}{800} = 1.25 \times 10^{- 3} \frac{r a d}{s}]$

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Gravitation Question 49

Question: The angular speed of earth, so that the object on equator may appear weightless, is [(g=10,m/s2] , radius of earth 6400 km)[Pb. PMT 2001]

Options:

Answer:

Solution:

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Question: The angular speed of earth, so that the object on equator may appear weightless, is $[(g = 10, m / s^{2}]$ , radius of earth 6400 km)[Pb. PMT 2001]