Gravitation Question 49

Question: The angular speed of earth, so that the object on equator may appear weightless, is $ [(g=10,m/s^{2}] $ , radius of earth 6400 km)[Pb. PMT 2001]

Options:

A) $ [1.25\times {{10}^{-3}}rad/sec] $

B) $ [1.56\times {{10}^{-3}}rad/sec] $

C) $ [1.25\times {{10}^{-1}}rad/sec] $

D) 1.56 rad/sec

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Answer:

Correct Answer: A

Solution:

For condition of weightlessness of equator

$ [\omega =\sqrt{\frac{g}{R}}=\frac{1}{800}=1.25\times {{10}^{-3}}\frac{rad}{s}] $



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