SATHEE: Gravitation Question 48

Gravitation Question 48

Question: Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If $[R_{e}]$ is the maximum range of a projectile on the earth’s surface, what is the maximum range on the surface of the moon for the same velocity of projection [Kerala (Engg.) 2001]

Options:

A) $[0.2, R_{e}]$

B) $[2, R_{e}]$

C) $[0.5, R_{e}]$

D) $[5, R_{e}]$

Show Answer

Answer:

Correct Answer: D

Solution:

Range of projectile $[R = \frac{u^{2} \sin 2 θ}{g}]$ if u and q are constant then $[R \propto \frac{1}{g}]$ $[\frac{R_{m}}{R_{e}} = \frac{g_{e}}{g_{m}} \Rightarrow \frac{R_{m}}{R_{e}} = \frac{1}{0.2} \Rightarrow R_{m} = \frac{R_{e}}{0.2}]$ Þ $[R_{m} = 5 R_{e}]$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Gravitation Question 48

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu