Gravitation Question 41
Question: The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes 1% of its value at the surface is (Radius of the earth = R) [EAMCET (Engg.) 2000]
Options:
A) 8 R
B) 9 R
C) 10 R
D) 20 R
Show Answer
Answer:
Correct Answer: B
Solution:
$ [\frac{{{g}’}}{g}={{\left( \frac{R}{R+h} \right)}^{2}}\Rightarrow \frac{1}{100}={{\left( \frac{R}{R+h} \right)}^{2}}\Rightarrow h=9R] $
