Gravitation Question 41

Question: The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes 1% of its value at the surface is (Radius of the earth = R) [EAMCET (Engg.) 2000]

Options:

A) 8 R

B) 9 R

C) 10 R

D) 20 R

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Answer:

Correct Answer: B

Solution:

$ [\frac{{{g}’}}{g}={{\left( \frac{R}{R+h} \right)}^{2}}\Rightarrow \frac{1}{100}={{\left( \frac{R}{R+h} \right)}^{2}}\Rightarrow h=9R] $



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