Gravitation Question 317

Question: Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If $ [{R_{e}}] $ is the maximum range of a projectile on the earth’s surface, what is the maximum range on the surface of the moon for the same velocity of projection

Options:

A) $ [0.2{R_{e}}] $

B) $ [2{R_{e}}] $

C) $ [0.5{R_{e}}] $

D) $ [5{R_{e}}] $

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Answer:

Correct Answer: D

Solution:

  • Range of projectile $ [R=\frac{u^{2}\sin 2\theta }{g}] $

    if u and $ [\theta ] $ are constant then $ [R\propto \frac{1}{g}] $ $ [\frac{R_{m}}{{R_{e}}}=\frac{g_{e}}{g_{m}}\Rightarrow \frac{R_{m}}{{R_{e}}}=\frac{1}{0.2}] $ $ [\Rightarrow R_{m}=\frac{{R_{e}}}{0.2}\Rightarrow R_{m}=5{R_{e}}] $



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